Specifically chemistry stemlords A 10.00 g sample of an unknown water soluble barium salt is treated with an excess of Na2SO4 to precipitate 11.21 g BaSO4. Which barium salt is it?

A. BaCl2

B. Ba(O2CH)2

C. Ba(NO3)2

D. BaBr2

Help

  • Eris235 [undecided]
    ·
    2 years ago

    A, BaCl2.

    Its a density problem

    Weight of non-barium part of barium salt = X

    Br + X = BR + SO4

    Br + X = 10g

    Br + SO4 = 11.21 g

    Molar mass of BrSO4 = 233.39 g/mol

    So you have 11.21/233.39= .048 mols of BrSO4

    10g/.064m = 208.2 g/mol

    Which of the answers has that molar mass?

    (its BaCl2, at 208.233g/mol)