You could do this in one line...

By removing all the linebreaks.

Programming humor on reddit used to be excellent bits like this but then it devolved into new learners jumping straight to the irony they didn't understand and flooded the sub with nonsense.

I miss these bits.

btw it does get easier

import math
def is_even(num):
    if num in [i for i in range(1000) if float(i)/2.0 == math.floor(float(i)/2.0)]:
        print("true")
    else:
        print("false")

Obviously one would need to increase the range for bigger numbers but this code is optimized.

def is_even(n):
    match n:
        case 1:
            return False
        case 0:
            return True
        # fix No1
        case n < 0:
            return is_even(-1*n)
        case _:
            return is_even(n-2)

This could be optimized by using a recursive function.

modulo

pseudocode:

if number % 2 == 0
  return "number is even" (is_num_even = 1 or true)
else
  return "number is odd" (is_num_even = 0 or false)

plus you'd want an input validation beforehand

God, this must go on for, like, twenty or so lines.

...btw a switch statement is better in this case(get it?)

there is!

Source tweet

You joke, but I've seen a programming language that didn't have a loop, and if you copied a line of text and pasted it in a text editor, JSON would come out...

The editor could barely handle 400+ lines because it probably converted the text to JSON, added a letter and converted it back to JSON... Per inserted symbol...

My solution in perl back in the day when I was a teenage hobbyist who didn't know about the modulus operator: Divide by 2 and use regex to check for a decimal point.

if ($num / 2 =~ /\./) { return "odd" }
else { return "even" }